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自 PHP 5.1.1 起有几个有用的可用作标准的日期／时间格式来指定
format 参数。
自 PHP 5.1 起在
中保存了发起该请求时刻的时间戳。
有效的时间戳典型范围是格林威治时间 1901 年 12 月 13 日 20:45:54
到 2038 年 1 月 19 日 03:14:07。（此范围符合 32
位有符号整数的最小值和最大值）。不过在 PHP 5.1 之前此范围在某些系统（如
Windows）中限制为从 1970 年 1 月 1 日到 2038 年 1 月 19 日。
要将字符串表达的时间转换成时间戳，应该使用
。此外一些数据库有一些函数将其时间格式转换成时间戳（例如
格式字串可以识别以下 format 参数的字符串
format 字符
返回值例子
月份中的第几天，有前导零的 2 位数字
星期中的第几天，文本表示，3 个字母
Mon 到 Sun
月份中的第几天，没有前导零
l（“L”的小写字母）
星期几，完整的文本格式
Sunday 到 Saturday
ISO-8601 格式数字表示的星期中的第几天（PHP 5.1.0 新加）
1（表示星期一）到 7（表示星期天）
每月天数后面的英文后缀，2 个字符
st，nd，rd
或者 th。可以和 j 一起用
星期中的第几天，数字表示
0（表示星期天）到 6（表示星期六）
年份中的第几天
ISO-8601 格式年份中的第几周，每周从星期一开始（PHP 4.1.0 新加的）
例如：42（当年的第 42 周）
月份，完整的文本格式，例如 January 或者 March
January 到 December
数字表示的月份，有前导零
三个字母缩写表示的月份
Jan 到 Dec
数字表示的月份，没有前导零
指定的月份有几天
是否为闰年
如果是闰年为 1，否则为 0
ISO-8601 格式年份数字。这和
Y 的值相同，只除了如果 ISO
的星期数（W）属于前一年或下一年，则用那一年。（PHP 5.1.0 新加）
Examples: 1999 or 2003
4 位数字完整表示的年份
例如：1999 或 2003
2 位数字表示的年份
例如：99 或 03
小写的上午和下午值
大写的上午和下午值
Swatch Internet 标准时
000 到 999
小时，12 小时格式，没有前导零
小时，24 小时格式，没有前导零
小时，12 小时格式，有前导零
小时，24 小时格式，有前导零
有前导零的分钟数
秒数，有前导零
毫秒 （PHP 5.2.2 新加）。需要注意的是
date() 函数总是返回
000000 因为它只接受
才支持毫秒。
示例: 654321
时区标识（PHP 5.1.0 新加）
例如：UTC，GMT，Atlantic/Azores
是否为夏令时
如果是夏令时为 1，否则为 0
与格林威治时间相差的小时数
例如：+0200
与格林威治时间（GMT）的差别，小时和分钟之间有冒号分隔（PHP 5.1.3 新加）
例如：+02:00
本机所在的时区
例如：EST，MDT（【译者注】在 Windows
下为完整文本格式，例如“Eastern Standard Time”，中文版会显示“中国标准时间”）。
时差偏移量的秒数。UTC 西边的时区偏移量总是负的，UTC 东边的时区偏移量总是正的。
-43200 到 43200
完整的日期／时间
ISO 8601 格式的日期（PHP 5 新加）
T15:19:21+00:00
RFC 822 格式的日期
例如：Thu, 21 Dec :07 +0200
从 Unix 纪元（January 1 :00 GMT）开始至今的秒数
格式字串中不能被识别的字符将原样显示。Z 格式在使用
时总是返回 0。
Example #1 date() 例子
&?php//&设定要用的默认时区。自&PHP&5.1&可用date_default_timezone_set('UTC');//&输出类似：Mondayecho&date("l");//&输出类似：Monday&15th&of&August&:46&PMecho&date('l&dS&\of&F&Y&h:i:s&A');//&输出：July&1,&2000&is&on&a&Saturdayecho&"July&1,&2000&is&on&a&"&.&date("l",&mktime(0,&0,&0,&7,&1,&2000));/*&在格式参数中使用常量&*///&输出类似：Wed,&25&Sep&:57&-0700echo&date(DATE_RFC2822);//&输出类似：T00:00:00+00:00echo&date(DATE_ATOM,&mktime(0,&0,&0,&7,&1,&2000));?&
在格式字串中的字符前加上反斜线来转义可以避免它被按照上表解释。如果加上反斜线后的字符本身就是一个特殊序列，那还要转义反斜线。
Example #2 在 date() 中转义字符
&?php//&prints&something&like:&Wednesday&the&15thecho&date("l&\\t\h\e&jS");?&
可以把 date() 和
函数结合使用来得到未来或过去的日期。
Example #3 date() 和
&?php$tomorrow&&=&mktime(0,&0,&0,&date("m")&&,&date("d")+1,&date("Y"));$lastmonth&=&mktime(0,&0,&0,&date("m")-1,&date("d"),&&&date("Y"));$nextyear&&=&mktime(0,&0,&0,&date("m"),&&&date("d"),&&&date("Y")+1);?&
由于夏令时的缘故，这种方法比简单地在时间戳上加减一天或者一个月的秒数更可靠。
一些使用 date()
格式化日期的例子。注意要转义所有其它的字符，因为目前有特殊含义的字符会产生不需要的结果，而其余字符在
PHP 将来的版本中可能会被用上。当转义时，注意用单引号以避免类似 \n 的字符变成了换行符。
Example #4 date() 格式举例
&?php//&假定今天是：March&10th,&:18&pm$today&=&date("F&j,&Y,&g:i&a");&&&&&&&&&&&&&&&&&//&March&10,&&pm$today&=&date("m.d.y");&&&&&&&&&&&&&&&&&&&&&&&&&//&03.10.01$today&=&date("j,&n,&Y");&&&&&&&&&&&&&&&&&&&&&&&//&10,&3,&2001$today&=&date("Ymd");&&&&&&&&&&&&&&&&&&&&&&&&&&&//&$today&=&date('h-i-s,&j-m-y,&it&is&w&Day&z&');&&//&05-16-17,&10-03-01,&&Fripm01$today&=&date('\i\t&\i\s&\t\h\e&jS&\d\a\y.');&&&//&It&is&the&10th&day.$today&=&date("D&M&j&G:i:s&T&Y");&&&&&&&&&&&&&&&//&Sat&Mar&10&15:16:08&MST&2001$today&=&date('H:m:s&\m&\i\s\&\m\o\n\t\h');&&&&&//&17:03:17&m&is&month$today&=&date("H:i:s");&&&&&&&&&&&&&&&&&&&&&&&&&//&17:16:17$today&=&date("Y-m-d&H:i:s");&&&&&&&&&&&&&&&&&&&//&&17:16:18&（MySQL&DATETIME&格式）?&
要格式化其它语种的日期，应该用
函数来代替 date()。
参见 ，，，
可以使用反斜线进行转义来阻止函数解析格式字符串中的可识别字符。
如果反斜线和要转义的字符连在一起依然是一个有效的字符序列，那么需要对
反斜线再次进行转义。
Example #6 对 date() 函数中的格式字符串进行转义
&?php//&输出类似：&Wednesday&the&15thecho&date('l&\t\h\e&jS');?&
可以联合使用 date()
来构造之前或者之后的日期时间。
Example #7 date() 和
联合使用示例
&?php$tomorrow&&=&mktime(0,&0,&0,&date("m")&&,&date("d")+1,&date("Y"));$lastmonth&=&mktime(0,&0,&0,&date("m")-1,&date("d"),&&&date("Y"));$nextyear&&=&mktime(0,&0,&0,&date("m"),&&&date("d"),&&&date("Y")+1);?&
由于存在夏令时时间，
所以此方案相对于直接在时间戳上加/减秒数
要更加可靠。
date() 函数格式化的一些示例。
需要注意的是，即使是对于当前来说并不具有特殊含义的字符，
也要像对待具有特殊含义的字符那样进行转义，以避免函数返回非预期的值。
因为可能在将来的 PHP 版本中，这些字符会被赋予特殊的含义。
进行转义的时候，请确保使用单引号，以避免 \n 被解释为换行符号。
Example #8 date() 函数格式化
&?php//&假设今天是&2001&年&3&月&10&日下午&5&点&16&分&18&秒，//&并且位于山区标准时间（MST）时区$today&=&date("F&j,&Y,&g:i&a");&&&&&&&&&&&&&&&&&//&March&10,&&pm$today&=&date("m.d.y");&&&&&&&&&&&&&&&&&&&&&&&&&//&03.10.01$today&=&date("j,&n,&Y");&&&&&&&&&&&&&&&&&&&&&&&//&10,&3,&2001$today&=&date("Ymd");&&&&&&&&&&&&&&&&&&&&&&&&&&&//&$today&=&date('h-i-s,&j-m-y,&it&is&w&Day');&&&&&//&05-16-18,&10-03-01,&&Satpm01$today&=&date('\i\t&\i\s&\t\h\e&jS&\d\a\y.');&&&//&it&is&the&10th&day.$today&=&date("D&M&j&G:i:s&T&Y");&&&&&&&&&&&&&&&//&Sat&Mar&10&17:16:18&MST&2001$today&=&date('H:m:s&\m&\i\s\&\m\o\n\t\h');&&&&&//&17:03:18&m&is&month$today&=&date("H:i:s");&&&&&&&&&&&&&&&&&&&&&&&&&//&17:16:18?&
如果需要将日期时间格式化为其他语言，你应该使用
来替代 date() 函数。
Things to be aware of when using week numbers with years.&?phpecho date("YW", strtotime("")); echo date("YW", strtotime("")); echo date("YW", strtotime("")); ?&BUT&?phpecho date("oW", strtotime("")); echo date("oW", strtotime("")); echo date("oW", strtotime("")); ?&Reason:Y is year from the dateo is ISO-8601 year numberW is ISO-8601 week number of yearConclusion:if using 'W' for the week number use 'o' for the year.
For Microseconds, we can get by following:echo date('Ymd His'.substr((string)microtime(), 1, 8).' e');Thought, it might be useful to someone !
Prior to PHP 5.6.23,& Relative Formats for the start of the week aligned with PHP's (0=Sunday,6=Saturday). Since 5.6.23,& Relative Formats for the start of the week align with ISO-8601 (1=Monday,7=Sunday). ()This can produce different, and seemingly incorrect, results depending on your PHP version and your choice of 'w' or 'N' for the Numeric representation of the day of the week: &?phpecho "Today is Sun 2 Oct 2016, day ",date('w',strtotime(''))," of this week. ";& echo "Day ",date('w',strtotime(' Monday next week'))," of next week is ",date('d M Y',strtotime(' Monday next week')),"&br /&";echo "Today is Sun 2 Oct 2016, day ",date('N',strtotime(''))," of this week. ";& echo "Day ",date('w',strtotime(' Monday next week'))," of next week is ",date('d M Y',strtotime(' Monday next week'));?& Prior to PHP 5.6.23, this results in: Today is Sun 2 Oct 2016, day 0 of this week. Day 1 of next week is 10 Oct 2016Today is Sun 2 Oct 2016, day 7 of this week. Day 1 of next week is 10 Oct 2016Since PHP 5.6.23, this results in: Today is Sun 2 Oct 2016, day 0 of this week. Day 1 of next week is 03 Oct 2016Today is Sun 2 Oct 2016, day 7 of this week. Day 1 of next week is 03 Oct 2016
this how you make an HTML5 &time& tag correctly&?phpecho '&time datetime="'.date('c').'"&'.date('Y - m - d').'&/time&';?&in the "datetime" attribute you should put a machine-readable value which represent time , the best value is a full time/date with ISO 8601 ( date('c') ) ,,, the attr will be hidden from usersand it doesn't really matter what you put as a shown value to the user,, any date/time format is okay !This is very good for SEO especially search engines like Google .
If you have a problem with the different time zone, this is the solution for that.&?php$defaultTimeZone='UTC';if(date_default_timezone_get()!=$defaultTimeZone)) date_default_timezone_set($defaultTimeZone);function _date($format="r", $timestamp=false, $timezone=false){& & $userTimezone = new DateTimeZone(!empty($timezone) ? $timezone : 'GMT');& & $gmtTimezone = new DateTimeZone('GMT');& & $myDateTime = new DateTime(($timestamp!=false?date("r",(int)$timestamp):date("r")), $gmtTimezone);& & $offset = $userTimezone-&getOffset($myDateTime);& & return date($format, ($timestamp!=false?(int)$timestamp:$myDateTime-&format('U')) + $offset);}echo 'System Date/Time: '.date("Y-m-d | h:i:sa").'&br&';echo 'New York Date/Time: '._date("Y-m-d | h:i:sa", false, 'America/New_York').'&br&';echo 'Belgrade Date/Time: '._date("Y-m-d | h:i:sa", false, 'Europe/Belgrade').'&br&';echo 'Belgrade Date/Time: '._date("Y-m-d | h:i:sa", , 'Europe/Belgrade').'&br&';?&This is the best and fastest solution for this problem. Working almost identical to date() function only as a supplement has the time zone option.
FYI: there's a list of constants with predefined formats on the DateTime object, for example instead of outputting ISO 8601 dates with:&?phpecho date('c');?&or&?phpecho date('Y-m-d\TH:i:sO');?&You can use&?phpecho date(DateTime::ISO8601);?&instead, which is much easier to read.
If timestamp is a string, date converts it to an integer in a possibly unexpected way:&?phpecho (int)'0x10'; echo intval('0x10'); echo date('s', '0x10'); echo date('s', '010'); ?&(PHP 5.6.16)
It's common for us to overthink the complexity of date/time calculations and underthink the power and flexibility of PHP's built-in functions.& Consider &?phpfunction get_time_string($seconds){& & return date('H:i:s', strtotime(" + $seconds SECONDS"));}
I've been flicking through the comments looking for some succinct date code and have noticed an alarming number of questions and over-burdened examples related to date mathematics. One of the most useful skills you can utilize when performing date math is taking full advantage of the UNIX timestamp. The UNIX timestamp was built for this kind of work.An example of this relates to a comment made by james at bandit-dot-co-dot-en-zed. James was looking for a way to calculate the number of days which have passed since a certain date. Rather than using mktime() and a loop, James can subtract the current timestamp from the timestamp of the date in question and divide that by the number of seconds in a day:&?php$days = floor((time() - strtotime("01-Jan-2006"))/86400);print("$days days have passed.\n");?&Another usage could find itself in a class submitted by Kyle M Hall which aids in the creation of timestamps from the recent past for use with MySQL. Rather than the looping and fine tuning of a date, Kyle can use the raw UNIX timestamps (this is untested code):&?php$ago = 14; $timestamp = time() - ($ago * 86400);?&Hopefully these two examples of "UNIX-style" timestamp usage will help those finding date mathematics more elusive than it should be.
&?phpfunction get_date_diff($start_time,$end_time=''){& & $end_time = ($end_time=='')?date("Y-m-d H:i:s"):$end_time;& & $datetime1 = new \DateTime($start_time);& & $datetime2 = new \DateTime($end_time);& & $interval = $datetime1-&diff($datetime2);& & $time['y'] = $interval-&format('%y');& & $time['m'] = $interval-&format('%m');& & $time['d'] = $interval-&format('%d');& & $time['h'] = $interval-&format('%H');& & $time['i'] = $interval-&format('%i');& & $time['s'] = $interval-&format('%s');& & $time['a'] = $interval-&format('%a');& & return $time;}print_r(get_date_diff(' 10:01:56'));
At least in PHP 5.5.38 date('j.n.Y', ) gives a result of 2.6.2040.So date is not longer limited to the minimum and maximum values for a 32-bit signed integer as timestamp.
In order to determine if a year is a leap year an earlier poster suggested simply checking to see if the year is a multiple of four:&?phpfunction is_leapyear_broken($year = 2004) {return ($year%4)==0;}?&While this will work for the majority of years it will not work on years that are multiples of 100 but not multiples of 400 i.e.(2100).A function not using php's date() function that will also account for this small anomaly in leap years:&?phpfunction is_leapyear_working($year = 2004) {& & if((($year%4==0) && ($year%100!=0)) || $year%400==0) {& & & & return true;& & }& & return false;}?&While is_leapyear_working will not return true for the few non-leap years divisible by four I couldn't tell you if this is more or less efficient than using php's date() as an even earlier poster suggested:&?phpfunction is_leapyear($year = 2004) {$is_leap = date('L', strtotime("$year-1-1"));return $is_leap;}?&
For HTML5 datetime-local HTML input controls () use format example: T16:39:57To generate this, escape the 'T', as shown below:&?phpdate('Y-m-d\TH:i:s');?&
Most spreadsheet programs have a rather nice little built-in function called NETWORKDAYS to calculate the number of business days (i.e. Monday-Friday, excluding holidays) between any two given dates. I couldn't find a simple way to do that in PHP, so I threw this together. It replicates the functionality of OpenOffice's NETWORKDAYS function - you give it a start date, an end date, and an array of any holidays you want skipped, and it'll tell you the number of business days (inclusive of the start and end days!) between them.I've tested it pretty strenuously but date arithmetic is complicated and there's always the possibility I missed something, so please feel free to check my math.The function could certainly be made much more powerful, to allow you to set different days to be ignored (e.g. "skip all Fridays and Saturdays but include Sundays") or to set up dates that should always be skipped (e.g. "skip July 4th in any year, skip the first Monday in September in any year"). But that's a project for another time.&?phpfunction networkdays($s, $e, $holidays = array()) {& & if ($s & $e)& & & & return networkdays($e, $s, $holidays);& & $sd = date("N", $s);& & $ed = date("N", $e);& & $w = floor(($e - $s)/(86400*7));& & if ($ed &= $sd) { $w--; }& & & & $nwd = max(6 - $sd, 0);& & $nwd += min($ed, 5);& & $nwd += $w * 5;& & & & foreach ($holidays as $h) {& & & & $h = strtotime($h);& & & & if ($h & $s && $h & $e && date("N", $h) & 6)& & & & & & $nwd--;& & }& & return $nwd;}$start = strtotime("1 January 2010");$end = strtotime("13 December 2010");$holidays = array();$holidays[] = "4 July 2010";& & & & & & $holidays[] = "6 September 2010";& & & & echo networkdays($start, $end, $holidays);& & ?&Or, if you just want to know how many work days there are in any given year, here's a quick function for that one:&?phpfunction workdaysinyear($y) {& & $j1 = mktime(0,0,0,1,1,$y);& & if (date("L", $j1)) {& & & & if (date("N", $j1) == 6)& & & & & & return 260;& & & & elseif (date("N", $j1) == 5 or date("N", $j1) == 7)& & & & & & return 261;& & & & else& & & & & & return 262;& & }& & else {& & & & if (date("N", $j1) == 6 or date("N", $j1) == 7)& & & & & & return 260;& & & & else& & & & & & return 261;& & }}?&
The following function will return the date (on the Gregorian calendar) for Orthodox Easter (Pascha).& Note that incorrect results will be returned for years less than 1601 or greater than 2399. This is because the Julian calendar (from which the Easter date is calculated) deviates from the Gregorian by one day for each century-year that is NOT a leap-year, i.e. the century is divisible by 4 but not by 10.& (In the old Julian reckoning, EVERY 4th year was a leap-year.)
This algorithm was first proposed by the mathematician/physicist Gauss.& Its complexity derives from the fact that the calculation is based on a combination of solar and lunar calendars.
&?php
function getOrthodoxEaster($date){
& $year = date("Y", $date);
& $r1 = $year % 19;
& $r2 = $year % 4;
& $r3 = $year % 7;
& $ra = 19 * $r1 + 16;
& $r4 = $ra % 30;
& $rb = 2 * $r2 + 4 * $r3 + 6 * $r4;
& $r5 = $rb % 7;
& $rc = $r4 + $r5;
& return strtotime("3 April $year + $rc days");
}
?&
Note that some formatting options are different from MySQL.For example using a 24 hour notation without leading zeros is the option '%G' in PHP but '%k' in MySQL.When using dynamically generated date formatting string, be careful to generate the correct options for either PHP or MySQL.
If you are having an issue getting u to work so is everyone else. The solution that I am using which I found on another site(so not taking credit) is to use this:& && date("Y/m/d H:i:s"). substr((string)microtime(), 1, 6);that will give you:& && yyyy/mm/dd hh:ii:ss.uuuuuuhope this helps someone in need!thanks all
Here's my solution for looking up the month number by name (used when parsing an 'ls'):
&?php
& for($m=1;$m&=12;$m++){
& & $month=date("M",mktime(0,0,0,$m,1,2000));
& & $mon["$month"]=$m;
& }
?&
&?php & & if(preg_match("/^[0-9]{4}(\/|-|.)(0[1-9]|1[0-2])(\/|-|.)(0[1-9]|[1-2][0-9]|3[0-1])$/", $date)){ & & & & return substr($date, 8, 2).substr($date, 7,1).substr($date, 5,2).substr($date, 4,1).substr($date, 0,4);& & & & }& & if(preg_match("/^(0[1-9]|[1-2][0-9]|3[0-1])(\/|-|.)(0[1-9]|1[0-2])(\/|-|.)[0-9]{4}$/", $date)){ & & & & return substr($date, 6, 4).substr($date, 5,1).substr($date, 3,2).substr($date, 2,1).substr($date, 0,2);& & & & }?&
To quickly convert date("N") to a 0 based index with Sunday being represented as 0, you can run it against modulus 7: &?php $first_of_month_index = date('N', strtotime('4/1/1990')) % 7;?&
Thanks to tcasparr at gmail dot com for the great idea (at least for me) ;)I changed the code a little to replicate the functionality of date_parse_from_format, once I don't have PHP 5.3.0 yet. This might be useful for someone. Hope you don't mind changing your code tcasparr at gmail dot com.&?phpfunction dateParseFromFormat($stFormat, $stData){& & $aDataRet = array();& & $aPieces = split('[:/.\ \-]', $stFormat);& & $aDatePart = split('[:/.\ \-]', $stData);& & foreach($aPieces as $key=&$chPiece)& & & & {& & & & switch ($chPiece)& & & & {& & & & & & case 'd':& & & & & & case 'j':& & & & & & & & $aDataRet['day'] = $aDatePart[$key];& & & & & & & && & & & & & & & & & & & & & case 'F':& & & & & & case 'M':& & & & & & case 'm':& & & & & & case 'n':& & & & & & & & $aDataRet['month'] = $aDatePart[$key];& & & & & & & && & & & & & & & & & & & & & case 'o':& & & & & & case 'Y':& & & & & & case 'y':& & & & & & & & $aDataRet['year'] = $aDatePart[$key];& & & & & & & && & & & & & & & & & & & case 'g':& & & & & & case 'G':& & & & & & case 'h':& & & & & & case 'H':& & & & & & & & $aDataRet['hour'] = $aDatePart[$key];& & & & & & & && & & & & & & & & & & & & & & & case 'i':& & & & & & & & $aDataRet['minute'] = $aDatePart[$key];& & & & & & & && & & & & & & & & & & & & & case 's':& & & & & & & & $aDataRet['second'] = $aDatePart[$key];& & & & & & & && & & & & & & & & & }& & & & & & }& & return $aDataRet;}?&Also, if you need to change the format of dates:&?phpfunction changeDateFormat($stDate,$stFormatFrom,$stFormatTo){& $date = dateParseFromFormat($stFormatFrom,$stDate);& return date($stFormatTo,mktime($date['hour'],& & & & & & & & & & & & & & & & & & $date['minute'],& & & & & & & & & & & & & & & & & & $date['second'],& & & & & & & & & & & & & & & & & & $date['month'],& & & & & & & & & & & & & & & & & & $date['day'],& & & & & & & & & & & & & & & & & & $date['year']));}?&
If you see the number 86400 in a date calculation, think very hard before deciding that it is correct. Not all days have 86,400 seconds in them. In many places, some days have only 82,800 seconds and some have 90,000. Occasionally, there are even fewer or even more.Assuming that now plus 86,400 seconds is equivalent to some time tomorrow can sometimes be wrong. It might actually be the day after tomorrow or still today.It's called Daylight Saving.
Correct format for a MySQL DATETIME column is&?php $mysqltime = date ("Y-m-d H:i:s", $phptime); ?&
In order to define leap year you must considre not only that year can be divide by 4!The correct alghoritm is:if (year is not divisible by 4) then (it is a common year)else if (year is not divisible by 100) then (it is a leap year)else if (year is not divisible by 400) then (it is a common year)else (it is a leap year)So the code should look like this:if($year%4 == 0 && $year%100 != 0) {& & $leapYear = 1;} elseif($year%400 == 0) {& & $leapYear = 1;& & & & & & & & & & & & && } else {& & $leapYear = 0;}
In order to define leap year you must considre not only that year can be divide by 4!The correct alghoritm is:if (year is not divisible by 4) then (it is a common year)else if (year is not divisible by 100) then (it is a leap year)else if (year is not divisible by 400) then (it is a common year)else (it is a leap year)So the code should look like this:if($year%4 == 0 && $year%100 != 0) {& & $leapYear = 1;} elseif($year%400 == 0) {& & $leapYear = 1;& & & & & & & & & & & & && } else {& & $leapYear = 0;}
In order to define leap year you must considre not only that year can be divide by 4!The correct alghoritm is:if (year is not divisible by 4) then (it is a common year)else if (year is not divisible by 100) then (it is a leap year)else if (year is not divisible by 400) then (it is a common year)else (it is a leap year)So the code should look like this:if($year%4 == 0 && $year%100 != 0) {& & $leapYear = 1;} elseif($year%400 == 0) {& & $leapYear = 1;& & & & & & & & & & & & && } else {& & $leapYear = 0;}
If you want to use HTML5's &date& tag, the following code will generate the machine-readable value for the 'datetime' attribute:&?phpfunction getDateTimeValue( $intDate = null ) {& & $strFormat = 'Y-m-d\TH:i:s.uP';& & $strDate = $intDate ? date( $strFormat, $intDate ) : date( $strFormat ) ; & & & & return $strDate;}echo getDateTimeValue();?&
Ayuda...Tengo una fecha asignada con la function date("w"), y exactamente a las 5 pm la fecha cambia al siguiente dia. Ejdate("w") - Lunesy a las 5pm del Lunes cambia a Martes.Que puede estar pasando
Since PHP 5.6.23 en 7.0.8 the support for requesting the weeknumber for a given date, where the first day of the week is Sunday, has been removed. For those of us still needing it, here is simple hack to get the job done.& & private function getWeeknumberSundayFirstDayOfWeek(\DateTimeInterface $date)& & {& & & & if ($date-&format('w') === 0) // Sunday& & & & & & return (int)$date-&format('W') - 1;& & & & return (int)$date-&format('W');& & }
If looking for a simple way to return the week number, using Sunday as the first day of the week, please bear in mind you will need to cater for the addition when you reach the end of the year.&?phpfunction getSundayWeekNumber(\DateTimeInterface $date): int{& & $weekNumber = (int)$date-&format('W');& & if ($date-&format('w') === '0') { $weekNumber += 1;& & & & if (53 === $weekNumber) { $weekNumber -= 52;& & & & }& & }& & return $weekNumber;}
When using 'U' to return a UNIX time stamp, you may not get what you expect. In the following example, we try to get the current Unix time stamp for a user in a different timezone.&?php$timezone = new \DateTimeZone($userTimeZone);$date = new \DateTime('@' . time(), $timezone);$date-&setTimezone($timezone);$now = $date-&format('U');?&$now will return the same (the server's current) Unix time stamp regardless which timezone your user is in.To get the actual Unix time stamp based on a time zone, replace format('U') as in t&?php$timezone = new \DateTimeZone($userTimeZone);$date = new \DateTime('@' . time(), $timezone);$date-&setTimezone($timezone);$now = $date-&getTimestamp() + $date-&getOffset();?&
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I am glad and wonder about the topic creation. I am visiting this page from a long time ago. This is totally perspective clear ideas. This is sure that the information you shared is clearly identive and fabulous for keeping it in minds.}