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/etc/nginx/nginx.conf.问一道数学题，求详细解答过程, 问一道数学题，求详细解答过程
问一道数学题，求详细解答过程 [(a+b)/2]^2-[(a-b)/2]^2 其中a=-1/8
先分解因式
然后再求值 \_猫_咪 问一道数学题，求详细解答过程
2]²2)=a*b=(-1/2+b&#47[(a+b)/2]-[(a-b)/-[(a-b)/2]}{[(a+b)/2+b/2]²2)(a/2]}=(a/8)*2=-1/2+a/2]+[(a-b)/2+b2-a/2-b/={[(a+b)&#47
2]²2)=a*b=(-1/2+b&#47[(a+b)/2]-[(a-b)/-[(a-b)/2]}{[(a+b)/2+b/2]²2)(a/2]}=(a/8)*2=-1/2+a/2]+[(a-b)/2+b2-a/2-b/={[(a+b)&#47
原式=[(a+b)/2+(a-b)/2][(a+b)/2-（a-b)/2]
=ab=-1/8×2=-1/4
[(a+b)/2]^2-[)(a-b/2]^2=[(a+b)^2-(a-b)^2]/4=[a^2-2ab+b^2-a^2+2ab-b^2]/4=ab=-1/8*2=-1/4
[(a+b)/2]²-[(a-b)/2]²={[(a+b)/2]+[(a-b)/2]}{[(a+b)/2]-[(a-b)/2]}=(a/2+b/2+a/2-b/2)(a/2+b2-a/2+b/2)=a*b=(-1/8)*2=-1/4
^是什么意思，是乘吗
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