高一化学 求解……………………/from=2001a/bd_page_type=1/ssid=0/uid=0/pu=usm%400%2Csz%%2Cta%40big__5.0_1_8.9/baiduid=16FDFFEC81BE/w=0_10_%E5%A6%82%E4%B8%8B%E5%9B%BE%E6%89%80%E7%A4%BA%E6%98%AF%E6%B0%A8%E6%B0%A7%E7%87%83%E6%96%99%E7%94%B5%E6%B1%A0/t=wap/l=0/tc?ref=www_touch&lid=&order=1&vit=osres&tj=www_normal_1_0_10&dict=20&sec=37424&di=801dfe1&bdenc=1&nsrc=IlPT2AEptyoA_yixCFOxXnANedT62v3IEQGG_yFL2De5mkayxP4kHREsRDfbLXPTUS4c9GOKg1ZRtXLR07Ez7qQQrbdmpWcf7nzdbOnq6RTKZBV_fAFlQwWWIXVmyPjzk_求第四小题过程
锌的物质的量97.5/65=1.5mol因为镀锌溶液中锌离子是正二价所以需要1.5*2=3mol电子1molNH3反应N由负3价变为0价失去3摩电子所以需要1摩氨标况下为22.4L
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