x/1+2y/1为什么2y等于多少米2xy/x+2y

高数曲面积分。 计算I=∫∫S (x+2y+4z+5)²dS,其中S是八面体|x|+|y|+|z|-
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高数曲面积分。 计算I=∫∫S (x+2y+4z+5)²dS,其中S是八面体|x|+|y|+|z|
z=√(a^2-x^2-y^2),zx’=-x/ √(a^2-x^2-y^2),zy’=-y/ √(a^2-x^2-y^2),ds=√(zx’^2+zy’^2+1)dxdy= dxdy /√(a^2-x^2-y^2)I=∫∫(x+2y+z)ds=∫∫(x+2y+√(a^2-x^2-y^2))* dxdy /√(a^2-x^2-y^2)换元,x=r*cosθ,y=r*sinθ, dxdy=rdrdθ积分区间:0≤r≤a,0 ≤θ≤π/2,原式I=∫∫(r*cosθ+2 r*sinθ+√(a^2-r^2))* rdrdθ /√(a^2-r^2)=∫∫(r^2*cosθdrdθ /√(a^2-r^2)+2 ∫∫r^2*sinθdrdθ /√(a^2-r^2)+∫∫rdrdθ =∫(cosθ+2sinθ)dθ∫(r^2* dr /√(a^2-r^2) +∫dθ∫rdr=(sinθ-2cosθ)(0-&π/2)*[-r/2*√(a^2-r^2)+1/2*a^2*arcsin(r/a)](0-&a)+ π/2*1/2*r^2(0-&a)=3*π/4*a^2+π/4*a^2=πa^2
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求过两圆x2+y2+4x+y=-1,x2+y2+2x+2y+1=0的交点的圆中面积最小的圆的方程。
2X-35 Y=-6&#47求过两圆x2+y2+4x+y=-1
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违法信息举报邮箱:1,求高等数学Z=arctan[(x+y)/(x-y)]的全微分 2,求z=arctan[(x+y)]/(1-xy)]的全微分_百度知道
1,求高等数学Z=arctan[(x+y)/(x-y)]的全微分 2,求z=arctan[(x+y)]/(1-xy)]的全微分
我有更好的答案
采纳率:83%
1(x+y)/(x-y)=1+2y/(x-y)[(x+y)/(x-y)]'x=2y'/(x-y) -2y(1-y')/(x-y)^2[(x+y)/(x-y)]'y=2/(x-y)+2y(-1)/(x-y)^2
1+(x+y)^2/(x-y)^2=2x^2+2y^2/(x-y)^2dz=[(dy/dx)(x-y)-y(1-dy/dx)]/(x^2+y^2)
*dx + (x-2y)/(x^2+y^2)
dy2[(x+y)/(1-xy)]'x=(1+y')/(1-xy)-(x+y)(-y-xy')/(1-xy)^2[(x+y)/(1-xy)]'y=(1+x')/(1-xy)-(x+y)(-x-x'y)/(1-xy)^2
1+(x+y)^2/(1-xy)^2=[(x+y)^2+(1-xy)^2]/(1-xy)^2dz=[(1+dy/dx)(1-xy)-(x+y)(-y-xdy/dx)]/[(1-xy)^2+(x+y)^2] dx
+ [(1+dx/dy)(1-xy)-(x+y)(-x-ydx/dy)]/[(1-xy)^2+(x+y)^2] dy
诶,答案不对。第一个答案是,dz=(xdy-ydx)/(x²+y²)第二个答案是,dz=dx/(1+x^2)+dy/(1+y^2)
本回答被网友采纳
1、dz=(xdy-ydx)/(x²+y²)2、dz=[(1+y²)dx+(1+x²)dy]/[(1-xy)²+(x+y)²]
第一个答案是对的,可有详解?第二个答案不对,答案是dx/(1+x^2)+dy/(1+y^2)
dz=[(1+y²)dx+(1+x²)dy]/[(1-xy)²+(x+y)²]=dx/(1+x^2)+dy/(1+y^2)
你好!&&&&这两道题的详细过程见插入的图片&,点击一次图片后出现一个小图片,再点击一次便出现放大的图片。
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SuperH patches against 3.2 :00 (incorporating 3.2.1 ) (1/2)
From: Joern Rennecke &joern dot rennecke at superh dot com&
To: gcc-patches at gcc dot gnu dot org
Date: Mon, 20 Sep :26 +0100 (BST)
Subject: SuperH patches against 3.2 :00 (incorporating 3.2.1 ) (1/2)
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