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你可能喜欢VB编写程序,生成一个10个元素的随机整数组,数组元素的范围0-100,要求将这个数组的最大值和最小值的位置对调
VB编写程序,生成一个10个元素的随机整数组,数组元素的范围0-100,要求将这个数组的最大值和最小值的位置对调
dim a(10) as integerdim i as integer,k as integer,p as integerdim m as integerdim n as integerfor i=1 to 10a(i)=int(rnd()*101)next ik=-1p=101for i=1 to 10if a(i)>k thenk=a(i)m=iendifif a(i)
与《VB编写程序,生成一个10个元素的随机整数组,数组元素的范围0-100,要求将这个数组的最大值和最小值的位置对调》相关的作业问题
/>private sub command1_click()dim a(1 to 10) as doubledim min as doublefor i=1 to 10 a(i)=val(inputbox("请输入数组元素值："))next ifor i=1 to 10 if a(i)
两种方法1 补充你的算法,Private Sub Command1_Click()Dim a(10) As Integer,n As IntegerDim i As Integer,k As IntegerRandomizea(1) = Int(Rnd * 90) + 10k = 1Don = Int(Rnd * 90
同时与n互质的数 ------这个不太明白?能说一下吗? 下面1000以内质数算法.Private Sub Command1_Click()Text1.Text = ""For i = 1 To 1000k = 1For j = 2 To i / 2If i Mod j = 0 Then k = 0Next jIf k
这样才完整：判断不出错.N-1省去了许多判断,提高了效率.Private Sub Command1_Click()Dim N As IntegerDim i As IntegerIf IsNumeric(Text1.Text) ThenIf N > 0 And N < 100 ThenN = Val(Text1.Tex
#include #include int main(){ int arr[40],i,t=1; arr[0]=0;arr[1]=1; for(i=2;i
这么简单你还上来求助. 再问： 就是不会啊、、才学的、、麻烦你 告诉我谢谢了 再答： Private Sub Command1_Click() Dim i As Byte Dim a(11), sum, pingjunzhi As Single sum = 0 For i = 1 To 10 a(i) = 81 * R
楼主看看这个：Private&Sub&Command1_Click()&&&Dim&aNum(9)&As&Long,&V&As&Long&&&Dim&nMax&
假设矩阵为一个数组a(1 to m,1 to n)Sub Max()Dim b() As Single,maxx As SingleFor i = 1 To mb(i) = a(i,1)For j = 1 To nIf b(i)
Private Sub Command1_Click()ClsDim a(1 To 10) As IntegerFor i = 1 To 10Randomizea(i) = Int(Rnd * 90 + 10)For j = 1 To i - 1If a(i) = a(j) Theni = i - 1Exit ForE
#include#include#include#includemain(){int i,j,t,a[10];double sum=0;srand(time(0));/*产生随机数,并输出各个元素*/printf("随机数数组的各元素为：\n");for(i=0;i
（1）0与1构成的二维数组：CLS :n = 1 FOR i = 1 TO 10 FOR j = 1 TO 10 IF i = n AND j = n THEN a(i,j) = 0:a(i,10 - j + 1) = 0 IF i = 5 THEN x = 9 - j - 1 ELSE x = 9 - jELSEIF
你的条件是要同时满足还是满足其中一个就够了?如果全部满足就是我这种,如果是满足一种就是楼上的那种private sub form1_click()dim i as integer,s as singles=0for i=10 to 1000 step 1if i mod 4=3 and i mod 7=4 and i
关于你说的变量的声明（定义）问题,你需要掌握变量的作用域的概念：我给你一个例子,看看能否了解.
Private Sub Command1_Click()For a = 1 To 4 '20元For b = 1 To 9 '10元For c = 1 To 19 '5元If a * 20 + b * 10 + c * 5 = 100 ThenPrint "20元: "; a, "10元: "; b, "5元"; cE
#include&&stdio.h&#include&&stdlib.h&#include&&time.h&#define&MAXlen&20int&main()&{int&i,k,a[MAXlen],
Dim n As IntegerDim m As IntegerFor n = 10 To 1000If (n Mod 4) = 3 And (n Mod 7) = 5 And (n Mod 9) = 2 Then m = m + nNext nPrint m
Private Sub Command1_Click()Dim i As Integer,bb(20) As Integer'1Dim k As Integer,dbl1 As DoubleFor i = 1 To 20Randomizebb(i) = Int(Rnd * 101)bb(0) = bb(0) + bb(
Dim a(1 To 16)Private Sub Command1_Click()For i = 1 To 16Randomizea(i) = Int(Rnd * 90 + 10)If i Mod 4 = 0 ThenText1 = Text1 & a(i) & vbCrLfElseText1 = Text1 & a
是求对角线元素的行与列之和吧,如果是那么以这种格式如第一行第一列：1+1=2,输出还是直接把得数2输出来还是说要把10*10的矩形输出来,再输出对角线元素的和.编写一个程序,该程序读取整数,直到输入0为止,输入终止后,报告输出偶数个数,偶数平均数,奇数个数,奇数平均数.
void main() {
int n1, n2, sum1, sum2;
double avg1, avg2;
while (1) {
scanf("%d", &get);
if (get == 0)
if (get%2 == 0) {
avg1 = sum1/n1;
avg2 = sum2/n2;
printf("偶数个数: %d, 偶数平均数: %f\n", n1, avg1);
printf("奇数个数: %d, 奇数平均数: %f\n", n2, avg2);
其他答案（共5个回答）
void main()
{
int count_odd, count_
float sum_odd, sum_
int number,
count_odd = count_even = i = 0;
sum_odd = sum_even = 0.0;
#include <std相关信息.h>
void main()
{
int count_odd, count_
float sum_odd, sum_
int number,
count_odd = count_even = i = 0;
sum_odd = sum_even = 0.0;
printf("Input number %d: ", ++i);
scanf("%d", &number);
if (number == 0)
if (number % 2 == 0)
count_even++;
sum_even +=
count_odd++;
sum_odd +=
if (count_odd == 0 && count_even == 0)
printf("Just 0 input.\n");
//保证被除数不为0
printf("\nThe number of odd numbers is: %d, and the
average is: %5.2f\n", count_odd, count_odd==0 ? 0 : sum_odd/count_odd);
printf("The number of even numbers is: %d, and the average is: %5.2f\n", count_even, count_even==0 ? 0 :sum_even/count_even);
int main()
int a,sum1=0,sum2=0,total1=0,total2=0;
while(scanf("%d",&a))
if(a==0) return 0;
if(a%2==0) {sum1+=a;total1++};
else {sum2+=a;total2++;}
printf("偶数个数: %d, 偶数平均数: %f\n", sum1, float(sum1)/total1);
printf("奇数个数: %d, 奇数平均数: %f\n", sum2, float(sum2)/total2);
int main()
int Num,Count
= 0,Sum = 0;
while(scanf(&#034;%d&#034;,&Num)&&Num!=...
定义个足够大的数组，把输入的N个整数作为数组的前N个元素。
先用基本的算法把这个数组的前N个数排序，然后按排好的顺序输出这前N个数就行了。
#include &#034;...
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一般情况你是做不到的，因为数据前面有0没0是输入输出的问题，不是数据存储的问题，在程序运行过程中，变量中的数据是不带前面的0的。解决办法一、输入宽度与输出所定义...
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