3xmxn=梦幻3x神器多少积分?

display image as (r, g, b) from a (3xMxN) nympy.array
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display image as (r, g, b) from a (3xMxN) nympy.array
Hi All,i've data store in a multydimension numpy.array,it is composed by 3 MxN normalized (0 - 1) array&but tring to display it using "imshow" i get an error,"&TypeError: Invalid dimensions for image data "please can you help me to fix this problem ?my data is :&In [119]: dd[0]
array([[[ 1.
0.2519685 ,
0.2480315 ,
0.5984252 , ...,
0.2480315 ,
0.2519685 ,
0.4015748 , ...,
0.5984252 , ...,
0.2519685 ,
0.2519685 ,
0.]]])In [120]: len(dd[0])
Out[120]: 3
In [121]: dd[0].shape
Out[121]: (3, 2058, 2607)
In [122]: matplotlib.pyplot.imshow(dd[0])
------------------------------------------------------------
Traceback (most recent call last):
File "&ipython console&", line 1, in &module&
File "/Library/Python/2.6/site-packages/matplotlib/pyplot.py", line 2035, in imshow
ret = ax.imshow(X, cmap, norm, aspect, interpolation, alpha, vmin, vmax, origin, extent, shape, filternorm, filterrad, imlim, resample, url, **kwargs)
File "/Library/Python/2.6/site-packages/matplotlib/axes.py", line 6272, in imshow
im.set_data(X)
File "/Library/Python/2.6/site-packages/matplotlib/image.py", line 372, in set_data
raise TypeError("Invalid dimensions for image data")
TypeError: Invalid dimensions for image data
thanks for any help!!!Massimo.------------------------------------------------------------------------------
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Re: display image as (r, g, b) from a (3xMxN)
nympy.array
On Sat, Feb 27, 2010 at 11:04 PM, Massimo Di Stefano
& i've data store in a multydimension numpy.array,
& it is composed by 3 MxN normalized (0 - 1) array
& but tring to display it using &imshow& i get an error,
& & TypeError: Invalid dimensions for image data &
& please can you help me to fix this problem ?
& my data is :
& In [120]: len(dd[0])
& Out[120]: 3
& In [121]: dd[0].shape
& Out[121]: (3, )
& In [122]: matplotlib.pyplot.imshow(dd[0])
& ------------------------------------------------------------
& Traceback (most recent call last):
& & File &&ipython console&&, line 1, in &module&
& & File &/Library/Python/2.6/site-packages/matplotlib/pyplot.py&, line 2035,
& in imshow
& & & ret = ax.imshow(X, cmap, norm, aspect, interpolation, alpha, vmin, vmax,
& origin, extent, shape, filternorm, filterrad, imlim, resample, url,
& **kwargs)
& & File &/Library/Python/2.6/site-packages/matplotlib/axes.py&, line 6272, in
& & & im.set_data(X)
& & File &/Library/Python/2.6/site-packages/matplotlib/image.py&, line 372, in
& set_data
& & & raise TypeError(&Invalid dimensions for image data&)
& TypeError: Invalid dimensions for image data
Your image data is 3xMxN, but according to the imshow docstring:
& MxNx3 -- RGB (float or uint8 array)&
So a quick way is to use the transpose do:
matplotlib.pyplot.imshow(dd[0].transpose())
However, this will rotate the image (result will have N rows and M
columns), if you're expecting it to have M rows and N columns. In that
case, you need to &roll& the axis to the end, which will end up with a
3xMxN array:
&&&dd[0].shape
&&&data2 = np.rollaxis(dd[0], 0, 3)
&&&data2.shape
plt.imshow(data2)
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School of Meteorology
University of Oklahoma
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Loading...已知抛物线y=mx2+n向下平移2个单位后得到的函数图像是y=3x2-1,求m,n 的值. 9.如图,是一座抛物线形拱桥,水位在AB位置时,水面宽4米,水位上升3米达到警戒线MN位置时 ,水面宽4——精英家教网——
成绩波动大?难提高?听顶级名师视频辅导,
已知抛物线y=mx2+n向下平移2个单位后得到的函数图像是y=3x2-1,求m,n 的值. 9.如图,是一座抛物线形拱桥,水位在AB位置时,水面宽4米,水位上升3米达到警戒线MN位置时 ,水面宽4米,某年发洪水,水位以每小时0.25米的速度上升,求水过警戒线后几小时淹到拱桥顶? 【】
题目列表(包括答案和解析)
已知抛物线y=mx2+n向下平移2个单位后得到的函数图像是y=3x2-1,求m、n的值.&
已知抛物线y=mx2+n向下平移2个单位后得到的函数图像是y=3x2-1,求m,n 的值.
已知抛物线y=mx2+n向下平移2个单位后得到的函数图像是y=3x2-1,求m、n的值
已知抛物线y=mx2+n向下平移2个单位后得到的函数图像是y=3x2-1,求m、n的值.
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请输入手机号(1)化简并求值:a-[4b-c-(a-c)]+[6a-(b-c)].其中a=0.1.b=0.2.c=0.3,(2)已知A=2x-3y+1.B=3x+2y.求2A-B,(3)若m-n=4.mn=-1.求-的值. 题目和参考答案——精英家教网——
成绩波动大?难提高?听顶级名师视频辅导,
& 题目详情
(1)化简并求值:a-[4b-c-(a-c)]+[6a-(b-c)],其中a=0.1,b=0.2,c=0.3;(2)已知A=2x-3y+1,B=3x+2y,求2A-B;(3)若m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值.
解:(1)a-[4b-c-(a-c)]+[6a-(b-c)]=a-4b+c+(a-c)+6a-(b-c)=a-4b+c+a-c+6a-b+c=7a-5b+c当a=0.1,b=0.2,c=0.3时,原式=7×0.1-5×0.2+0.3=0;(2)∵A=2x-3y+1,B=3x+2y∴2A-B=2(2x-3y+1)+2(3x+2y)=4x-6y+2+6x+4y=x-8y+2;(3)∵m-n=4,mn=-1∴(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=-6mn+3(m-n)当m-n=4,mn=-1时,原式=-6×(-1)+3×4=18.分析:(1)本题要先去括号再合并同类项,对原代数式进行化简,然后把a,b,c的值代入计算即可.(2)(3)整体代入求解,注意去括号时符号的变化,合并同类项时,只是系数相加减,字母与字母的指数不变.点评:解答时要去括号合并同类项,括号前面是负号,去掉符号和括号,括号里面的各项要变号,且先去中括号,再去小括号.
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3秒自动关闭窗口3x的m次方减n减1的差乘x加1是x的二次二项式mn是多少
如果多项式3x的m次方减n减1的差乘x加1是关于x的二次二项式,是m,n的值。
09-02-21 &匿名提问
((3x)^m-n-1)*(x+1)=(3^m)x^(m+1)+(3x)^m-(n+1)x-n-1因为这个式子是x的二次二项式所以m+1=2     m=1代入得原式=3x^2+(2-n)x-n-1       所以 -n-1=0或者 2-n=0              n=-1或者2
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